The position of a particle is given by $ x=2\left(t-t^{2}\right) $, where $ t $ is expressed in seconds and $ x $ is in meter. The total distance travelled by the particle between $ \mathrm{t}=0 $ to $ \mathrm{t}=1 \mathrm{~s} $ is:

Question

The position of a particle is given by $ x=2\left(t-t^{2}\right) $, where $ t $ is expressed in seconds and $ x $ is in meter. The total distance travelled by the particle between $ \mathrm{t}=0 $ to $ \mathrm{t}=1 \mathrm{~s} $ is:, $ 0 \mathrm{~m} $, $ 1 \mathrm{~m} $, $ 2 \mathrm{~m} $, $ \frac{1}{2} \mathrm{~m} $

MARKS App · Accepted Answer

Let the total distance be s between for 0 t 1 We have x = 2 ( t - t 2 ) For 0 t 1 2 the displacement is s 1 = 1 2 for 1 2 t 1 the displacement is s 2 = - 1 2 distance s = s 1 + s 2 s = 1 2 + 1 2 = 1 m

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