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Question: Answered & Verified by Expert
The position of a particle related to time is given by x=(5t2-4t+5) m. The magnitude of velocity of the particle at t=2 s will be :
PhysicsMotion In One DimensionJEE MainJEE Main 2023 (15 Apr Shift 1)
Options:
  • A 06 m s-1
  • B 14 m s-1
  • C 10 m s-1
  • D 16 m s-1
Solution:
2311 Upvotes Verified Answer
The correct answer is: 16 m s-1

It is given that

x=5t2-4t+5

The velocity is given by 

v=dxdt=d(5t2-4t+5)dt=10t -4 

At t=2 s,

v=10(2)-4=16 m s-1

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