Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The potential energy for a force field F is given by U(x, y)=cos (x + y). The force acting on a particle at the position given by coordinates 0 π / 4  is 
PhysicsWork Power EnergyNEET
Options:
  • A - 1 2 i ^ + j ^
  • B 1 2 i ^ + j ^
  • C 1 2 i ^ + 3 2 j ^
  • D 1 2 i ^ - 3 2 j ^
Solution:
2971 Upvotes Verified Answer
The correct answer is: 1 2 i ^ + j ^
F x = - U x = sin x + y ,   F y = - U x = sin x + y

F x = sin x + y ] 0 π / 4 = 1 2 ,

F y = sin x + y ] 0 π / 4 = 1 2

∴    F = 1 2 i ^ + j ^

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.