Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The power of a lens (biconvex) is 1.25 m-1 in particular medium. Refractive index of the lens is 1.5 and radii of curvature are 20 cm and 40 cm respectively. The refractive index of surrounding medium:
PhysicsRay OpticsJEE MainJEE Main 2022 (28 Jul Shift 2)
Options:
  • A 1.0
  • B 97
  • C 32
  • D 43
Solution:
2160 Upvotes Verified Answer
The correct answer is: 43

Using Len's maker formula,

P=1f=μ1-μ21R1-1R2 

Where, μ1 is refractive index of lens and μ2 is of surrounding medium. 

Putting the values, 

1.25=1.5-μ210.2+10.4

1.25×0.080.6=1.5-μ2

The refractive index of surrounding medium is μ2=43.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.