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The pressure $p$ of a gas is plotted against its absolute temperature $T$ for two different constant volumes, $V_1$ and $V_2$. When $V_1 \gt V_2$, the
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Curve for $V_2$ has a greater slope than that for $V_1$
At constant volumes $P \propto T$
$P=$ constant $T ; \quad P V=n R T \therefore P=\frac{n R}{V} T$
slope $=m=\frac{\eta R}{V} \because V_2 \lt V_1$
$\frac{m_1}{m_2}=\frac{V_2}{V_1} \therefore m_1 \lt m_2$ is curve for $V_2$ has a greater slope than for $V_1$
$P=$ constant $T ; \quad P V=n R T \therefore P=\frac{n R}{V} T$
slope $=m=\frac{\eta R}{V} \because V_2 \lt V_1$
$\frac{m_1}{m_2}=\frac{V_2}{V_1} \therefore m_1 \lt m_2$ is curve for $V_2$ has a greater slope than for $V_1$
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