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The principal value of
$\sin ^{-1}\left(-\frac{1}{2}\right)$ is
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$\sin ^{-1}\left(-\frac{1}{2}\right)$ is
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Verified Answer
The correct answer is:
$-\frac{\pi}{6}$
The principal value of
$\sin ^{-1}\left(-\frac{1}{2}\right)=\sin ^{-1} \sin \left(-30^{\circ}\right)=-\frac{\pi}{6}$
$\sin ^{-1}\left(-\frac{1}{2}\right)=\sin ^{-1} \sin \left(-30^{\circ}\right)=-\frac{\pi}{6}$
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