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Question: Answered & Verified by Expert
The principal value of $\sin ^{-1}\left(-\frac{1}{2}\right)$ is
MathematicsInverse Trigonometric FunctionsMHT CETMHT CET 2020 (15 Oct Shift 1)
Options:
  • A $\frac{\pi}{3}$
  • B $\frac{\pi}{6}$
  • C $-\frac{\pi}{3}$
  • D $-\frac{\pi}{6}$
Solution:
2181 Upvotes Verified Answer
The correct answer is: $-\frac{\pi}{6}$
$\sin ^{-1}\left(-\frac{1}{2}\right)=-\sin ^{-1} \frac{1}{2}=\frac{-\pi}{6}$

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