The probability distribution of a random variable X is given as X − 5 − 4 − 3 − 2 − 1 0 1 2 3 4 5 P ( X ) p 2 p 3 p 4 p 5 p 7 p 8 p 9 p 10 p 11 p 12 p Then, the value of p is

Question

The probability distribution of a random variable X is given as X − 5 − 4 − 3 − 2 − 1 0 1 2 3 4 5 P ( X ) p 2 p 3 p 4 p 5 p 7 p 8 p 9 p 10 p 11 p 12 p Then, the value of p is, 1 72, 3 73, 5 72, 1 74

MARKS App · Accepted Answer

Sum of Probabilities = 1 ⇒ p + 2 p + 3 p + 4 p + 5 p + 7 p + 8 p + 9 p + 10 p + 11 p + 12 p = 1 ⇒ 72 p = 1 ⇒ p = 1 72

$X$	$- 5$	$- 4$	$- 3$	$- 2$	$- 1$	$0$	$1$	$2$	$3$	$4$	$5$
$P (X)$	$p$	$2 p$	$3 p$	$4 p$	$5 p$	$7 p$	$8 p$	$9 p$	$10 p$	$11 p$	$12 p$

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