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The products formed in the reaction of phenol with $\mathrm{Br}_2$ dissolved in $\mathrm{CS}_2$ at $0^{\circ} \mathrm{C}$ are
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o-bromo and $p$-bromophenols
Phenol when treated with $\mathrm{Br}_2$ in the presence of non-polar solvent $\mathrm{CS}_2$, it gives only o- and $p$-bromophenols instead the trisubstituted products. Reason for the above observation is supression of phenoxide ion in non-polar solvent. Thus, we get only mono substituted products.
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