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The quality factor of $L C R$ circuit having resistance $(R)$ and inductance $(L)$ at resonance frequency $(\omega)$ is given by
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Verified Answer
The correct answer is:
$\frac{\omega L}{R}$
As we know,
Quality factor $Q=\frac{V_L}{V_R}=\frac{X_L}{R}$
since, $X_L=\omega L$ then,
$Q=\frac{\omega L}{R}$
Quality factor $Q=\frac{V_L}{V_R}=\frac{X_L}{R}$
since, $X_L=\omega L$ then,
$Q=\frac{\omega L}{R}$
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