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The radioactive isotope \({ }_{27}^{60} \mathrm{Co}\) which is used in the treatment of cancer can be made by (\(n, p\)) reaction. For this reaction the target nucleus is
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\({ }_{28}^{60} \mathrm{Ni}\)
\([\mathrm{X}]+{ }_0^1 \mathrm{n} \rightarrow{ }_{27}^{60} \mathrm{Co}+{ }_1^1 \mathrm{H}\)
Balancing the mass and atomic numbers on both sides \({ }_{28}^{60} \mathrm{X}+{ }_0^1 \mathrm{n} \rightarrow{ }_{27}^{60} \mathrm{Co}+{ }_1^1 \mathrm{H}\)
Thus \(\mathrm{X}\) should be \({ }_{28}^{60} \mathrm{Ni}\)
Balancing the mass and atomic numbers on both sides \({ }_{28}^{60} \mathrm{X}+{ }_0^1 \mathrm{n} \rightarrow{ }_{27}^{60} \mathrm{Co}+{ }_1^1 \mathrm{H}\)
Thus \(\mathrm{X}\) should be \({ }_{28}^{60} \mathrm{Ni}\)
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