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The radius of the nucleus of an atom whose mass number is 125 is
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$6 \times 10^{-15} \mathrm{~m}$
$\begin{aligned} & R=R_0 A^{1 / 3} \\ & =1.2 \times 10^{-15} \times(125)^{1 / 3} \\ & =1.2 \times 10^{-15} \times(5)^{3 \times \frac{1}{3}} \\ & =6 \times 10^{-15} \mathrm{~m} .\end{aligned}$
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