The rate constant for a first order reaction is $60 \mathrm{~s}^{-1}$. How much time will it take to reduce the initial concentration of the reactant to its $\frac{1}{16^{\text {th }}}$ value?

Question

The rate constant for a first order reaction is $60 \mathrm{~s}^{-1}$. How much time will it take to reduce the initial concentration of the reactant to its $\frac{1}{16^{\text {th }}}$ value?,

MARKS App · Accepted Answer

$t=\frac{2 \cdot 303}{k} \log \frac{a}{a / 16}=\frac{2 \cdot 303}{60 \mathrm{~s}^{-1}} \log 16$ $=4.62 \times 10^{-2} \mathrm{~s}$

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