The rate constant for the decomposition of hydrocarbons is 2.418 × 10 –5 s –1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of the pre-exponential factor?

Question

The rate constant for the decomposition of hydrocarbons is 2.418 × 10 –5 s –1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of the pre-exponential factor?, 4.8 × 10 12 s –1, 1.2 × 10 12 s –1, 6.8 × 10 12 s –1, 3.9 × 10 12 s –1

MARKS App · Accepted Answer

Correct Option is : (D) 3.9 × 10 12 s –1

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