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Question: Answered & Verified by Expert
The rate of chemical reaction doubles with every 10oC rise in temperature. If the reaction is carried out in the vicinity of 22oC, the activation energy of the reaction is (Given R=8.3 J K-1 mol-1, ln 2=0.69 and ln 3=1.1)
ChemistryChemical KineticsTS EAMCETTS EAMCET 2020 (09 Sep Shift 1)
Options:
  • A 1.69 kJ mol-1
  • B 0.169 kJ mol-1
  • C 49.8 kJ mol-1
  • D 498 J mol-1
Solution:
1853 Upvotes Verified Answer
The correct answer is: 49.8 kJ mol-1

It is given that rate of a chemical reaction doubled with every rise so So k2k1=2 T1=10+273=283K T2=22+273=295K Now according to activation energy equation , Log k2k1=Ea2.303R [1T1-1T2]Log 2=Ea2.303R [1283-1295]Ea =49.8 kJmol-1

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