The ratio of de-Broglie wavelength of an α -particle and a proton accelerated from rest by the same potential is 1 m , the value of m is:

Question

The ratio of de-Broglie wavelength of an α -particle and a proton accelerated from rest by the same potential is 1 m , the value of m is:, 4, 16, 8, 2

MARKS App · Accepted Answer

As we know, de Broglie wavelength in terms of energy of particle is given by, λ = 1 2 m E . Energy gained by proton, E = q V . Therefore, λ α λ p = h 2 m α q α V h 2 m p q p V ⇒ λ α λ p = 1 8 ⇒ m = 8

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