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The ratio of radii of $3^{\text {rd }}$ and $6^{\text {th }}$ Bohr's orbit in a hydrogen atom is
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$0.25$
We have,
$\frac{\mathrm{r}_3}{\mathrm{r}_6}=\frac{3^2}{6^2}=\frac{9}{36}=0.25 \quad\left[\because \mathrm{r}_{\mathrm{n}} \propto \mathrm{n}^2\right]$
$\frac{\mathrm{r}_3}{\mathrm{r}_6}=\frac{3^2}{6^2}=\frac{9}{36}=0.25 \quad\left[\because \mathrm{r}_{\mathrm{n}} \propto \mathrm{n}^2\right]$
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