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The reaction for obtaining the metal (M) from its oxide $\left(\mathrm{M}_{2} \mathrm{O}_{3}\right)$ ore is given by
$\mathrm{M}_{2} \mathrm{O}_{3}(\mathrm{~s})+2 \mathrm{Al}(\ell) \stackrel{\text { Heat }}{\rightarrow} \mathrm{Al}_{2} \mathrm{O}_{3}(\ell)+2 \mathrm{M}(\mathrm{s}),(\mathrm{s}=$ solid, $\ell=$ liquid $)$
in that case, $M$ is
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$\mathrm{M}_{2} \mathrm{O}_{3}(\mathrm{~s})+2 \mathrm{Al}(\ell) \stackrel{\text { Heat }}{\rightarrow} \mathrm{Al}_{2} \mathrm{O}_{3}(\ell)+2 \mathrm{M}(\mathrm{s}),(\mathrm{s}=$ solid, $\ell=$ liquid $)$
in that case, $M$ is
Solution:
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Verified Answer
The correct answer is:
Iron
Hint:
Thermite Process
Thermite Process
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