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Question: Answered & Verified by Expert
The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3 . Compounds (B) and (C) respectively, are
Chemistryp Block Elements (Group 13 & 14)NEET
Options:
  • A Borazine and MeBr
  • B Boron nitride and MeBr
  • C Diborane and MeMgBr
  • D Borazine and MeMgBr
Solution:
2055 Upvotes Verified Answer
The correct answer is: Borazine and MeMgBr
Here B is Borazine and C is MeMgBr. The reactions are as follows
B3N3H3Cl3A+LiBH4B3N3H6BInorganicBenzeneor Borazine
B3N3H3Cl+MeMgBrCB3N3H3CH33+3MgBrCl

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