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Question: Answered & Verified by Expert
The reaction of methyltrichloroacetate $\left(\mathrm{Cl}_{3} \mathrm{CCO}_{2} \mathrm{Me}\right)$ with sodium methoxide $\mathrm({NaOMe})$ generates
ChemistryGeneral Organic ChemistryWBJEEWBJEE 2015
Options:
  • A carbocation
  • B carbene
  • C carbanion
  • D carbon radical
Solution:
1287 Upvotes Verified Answer
The correct answer is: carbene

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