The relationship between the force $ F $ and position $ x $ of a body is as shown in figure. The work done in displacing the body form $ x=1 \mathrm{~m} $ to $ x=5 \mathrm{~m} $ will be

Question

The relationship between the force $ F $ and position $ x $ of a body is as shown in figure. The work done in displacing the body form $ x=1 \mathrm{~m} $ to $ x=5 \mathrm{~m} $ will be, $ 30 \mathrm{~J} $, $ 15 \mathrm{~J} $, $ 25 \mathrm{~J} $, $ 20 \mathrm{~J} $

MARKS App · Accepted Answer

Work done = area under F - x graph = area of rectangle A B D C + area of rectangle E F H D + area of rectangle G J H I + area of triangle J K L . = 2 - 1 ( 10 - 0 ) + 3 - 2 5 - 0 + 4 - 3 - 5 - 0 + 1 2 5 - 4 10 - 0 = 15 J .

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