Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1.
ChemistryElectrochemistryNEET
Options:
  • A 1.46 cm⁻¹
  • B 0.15 cm⁻¹
  • C 1460 cm⁻¹
  • D 0.00146 cm⁻¹
Solution:
2502 Upvotes Verified Answer
The correct answer is: 0.15 cm⁻¹
Correct Option is : (B)
0.15 cm⁻¹

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.