The resistance of a conductivity cell containing $\mathbf{0} \cdot \mathbf{0 0 0 1} \mathrm{M}$ $\mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $1500 \Omega$. What is the cell constant if conductivity of $0.001 \mathrm{M} \mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $\mathbf{0} \cdot \mathbf{1 4 6} \times 10^{-3} \mathrm{~S} \mathrm{~cm}^{-1}$ ?

Question

The resistance of a conductivity cell containing $\mathbf{0} \cdot \mathbf{0 0 0 1} \mathrm{M}$ $\mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $1500 \Omega$. What is the cell constant if conductivity of $0.001 \mathrm{M} \mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $\mathbf{0} \cdot \mathbf{1 4 6} \times 10^{-3} \mathrm{~S} \mathrm{~cm}^{-1}$ ?,

MARKS App · Accepted Answer

Cell constant $=\frac{\text { Conductivity }}{\text { Conductance }}=$ Conductivity $\times$ Resistance $=0 \cdot 146 \times 10^{-3} \mathrm{~S} \mathrm{~cm}^{-1} \times 1500 \Omega$ $=0.219 \mathrm{~cm}^{-1}$.

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