Search any question & find its solution
Question:
Answered & Verified by Expert
The resultant gate and its Boolean expression in the given circuit is
Options:
Solution:
2465 Upvotes
Verified Answer
The correct answer is:
$AND, A.B$
Truth table:
\begin{array}{|l|l|l|l|l|}
\hline A & B & C & D & Y \\
\hline 0 & 0 & 1 & 1 & 0 \\
\hline 0 & 1 & 1 & 0 & 0 \\
\hline 1 & 0 & 0 & 1 & 0 \\
\hline 1 & 1 & 0 & 0 & 1 \\
\hline
\end{array}
This is truth table of AND gate. $\therefore \mathrm{Y}=\mathrm{A} \cdot \mathrm{B}$
\begin{array}{|l|l|l|l|l|}
\hline A & B & C & D & Y \\
\hline 0 & 0 & 1 & 1 & 0 \\
\hline 0 & 1 & 1 & 0 & 0 \\
\hline 1 & 0 & 0 & 1 & 0 \\
\hline 1 & 1 & 0 & 0 & 1 \\
\hline
\end{array}
This is truth table of AND gate. $\therefore \mathrm{Y}=\mathrm{A} \cdot \mathrm{B}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.