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The rms value of potential difference $v$ shown in the figure is
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Verified Answer
The correct answer is:
$\frac{v_{0}}{\sqrt{2}}$
$\mathrm{V}_{\mathrm{rms}}^{2} \times \mathrm{T}=\mathrm{V}_{0}^{2} \times \frac{\mathrm{T}}{2}+0$
$\mathrm{~V}_{\mathrm{rms}}^{2}=\frac{\mathrm{V}_{0}^{2}}{2} \quad \mathrm{~V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}$
$\mathrm{~V}_{\mathrm{rms}}^{2}=\frac{\mathrm{V}_{0}^{2}}{2} \quad \mathrm{~V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}$
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