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The roots of the equation $2 a^{2} x^{2}-2 a b x+b^{2}=0$ when. and $b>0$ are
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Always complex
We have, $2 a^{2} x^{2}-2 a b x+b^{2}=0$ Discriminent, $\mathrm{D}=(-2 \mathrm{ab})^{2}-4\left(2 \mathrm{a}^{2}\right)\left(\mathrm{b}^{2}\right)$
$=4 a^{2} b^{2}-8 a^{2} b^{2}=-4 a^{2} b^{2} < 0$
Roots are always complex.
$=4 a^{2} b^{2}-8 a^{2} b^{2}=-4 a^{2} b^{2} < 0$
Roots are always complex.
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