Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The salt which responds to dilute and concentrated \( \mathrm{H}_{2} \mathrm{SO}_{4} \) is
Chemistrys Block ElementsKCETKCET 2015
Options:
  • A \( \mathrm{CaF}_{2} \)
  • B \( B a\left(N O_{3}\right)_{2} \)
  • C \( \mathrm{Na}_{2} \mathrm{SO}_{4} \)
  • D \( \mathrm{Na}_{3} \mathrm{PO}_{4} \)
Solution:
2444 Upvotes Verified Answer
The correct answer is: \( B a\left(N O_{3}\right)_{2} \)
Reaction of \( \mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2} \) will \( \mathrm{H}_{2} \mathrm{SO}_{4} \) is a double displacement reaction in which precipitate of \( \mathrm{BaSO}_{4} \) will be formed,
therefore, reaction will proceed in forward direction even for low concentration of sulphuric acid.
\( \mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+2 \mathrm{HNO}_{3} \)

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.