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The set of all points, for which $f(x)=x^2 \cdot e^{-x}$ strictly increases, is
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Verified Answer
The correct answer is:
$(0,2)$
$$
f(x)=x^2 e^{-x}
$$
null
$f(x)$ is strictly increasing in $(0,2)$
f(x)=x^2 e^{-x}
$$
null
$f(x)$ is strictly increasing in $(0,2)$
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