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Question: Answered & Verified by Expert
The shortest distance from the point $(2,-7)$ to the circle $x^2+y^2-14 x-10 y-151=0$ is equal to 5 .
MathematicsConic Sections
Options:
  • A
    True
  • B
    False
Solution:
2319 Upvotes Verified Answer
The correct answer is:
False
No Solution Available

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