The shortest wavelength of hydrogen atom in Lyman series is λ . The longest wavelength in Balmer series of He + is

Question

The shortest wavelength of hydrogen atom in Lyman series is λ . The longest wavelength in Balmer series of He + is, 5 9 λ, 9 λ 5, 36 λ 5, 5 λ 9

MARKS App · Accepted Answer

For Hydrogen atom ( H ) ( Z = 1 ) : 1 λ H = R H × 1 2 1 1 2 - 1 ∞ 2 ...(1) For He + atom ( Z = 2 ) : 1 λ He + = R H × 2 2 × 1 2 2 - 1 3 2 = R H 1 - 4 9 = R H 5 9 ..(2) From (1) & (2) λ He + λ H = 9 5 λ He + = λ × 9 5 λ He + = 9 λ 5 .

Search any question & find its solution

Looking for more such questions to practice?