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The sides of a triangle are $x=2, y+1=0$ and $x+2 y=4$. Its circumcentre is
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Verified Answer
The correct answer is:
$(4,0)$
The vertices are $(2,-1),(6,-1),(2,1)$ forming a right angled triangle. Circumcentre is the mid-point of the hypotenuse,
i.e., $\quad\left(\frac{6+2}{2}, \frac{1-1}{2}\right)=(4,0)$
i.e., $\quad\left(\frac{6+2}{2}, \frac{1-1}{2}\right)=(4,0)$
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