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The slope of the normal at the point $\left(a t^2, 2 a t\right)$ of the parabola $y^2=4 a x$, is
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Verified Answer
The correct answer is:
$-t$
Normal is $y-2 a t_1=\frac{-2 a t}{2 a}\left(x-a t^2\right)$
Therefore, slope $=-t$.
Therefore, slope $=-t$.
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