Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The solubility product of Cr(OH)3 at 298K is 6.0×10-31. The concentration of hydroxide ions in a saturated solution of CrOH3 will be
ChemistryIonic EquilibriumJEE MainJEE Main 2020 (09 Jan Shift 2)
Options:
  • A 2.22×10-3114
  • B 18×10-3114
  • C 18×10-3112
  • D 4.86×10-2914
Solution:
1482 Upvotes Verified Answer
The correct answer is: 18×10-3114
CrOH3Cr+3+3O-
Ksp=s.3S3
6×10-31=27.3s4
s=627×10-311/4
OH-=3s
=3×627×10-3114=18×10-311/4M

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.