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The solution of the differential equation $\frac{d y}{d x}=x^2+\sin 3 x$ is
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The correct answer is:
$y=\frac{x^3}{3}-\frac{\cos 3 x}{3}+c$
$\frac{d y}{d x}=x^2+\sin 3 x$. On integrating, $y=\frac{x^3}{3}-\frac{\cos 3 x}{3}+c$
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