Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The solution of the equation sin2x+cos23x=1 is 
MathematicsTrigonometric EquationsJEE Main
Options:
  • A x=nπ3
  • B x=nπ+π4
  • C x=nπ4
  • D x=nπ+π2
Solution:
1156 Upvotes Verified Answer
The correct answer is: x=nπ4
sin2x=1-cos23x=sin23x
sin23x-sin2x=0
sin4xsin2x=0
sin2x=02x=nπx=nπ2
or
sin4x=04x=nπx=nπ4
x=nπ4

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.