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Question: Answered & Verified by Expert
The solution of the equation sin2x+cos2x=0, where π<x<2π are
MathematicsTrigonometric EquationsMHT CETMHT CET 2016
Options:
  • A 7π 8 , 11π 8
  • B 9π 8 ,  13π 8
  • C  11π 8 ,  15π 8
  • D 15π 8 ,  19π 8
Solution:
1679 Upvotes Verified Answer
The correct answer is:  11π 8 ,  15π 8
Given,
sin2x+cos2x=0 .
Multiplying by 12 on both side,
 12sin2x+12cos2x=0
 sin π4+2x=0
  2x+π4=nπ
  x=4n-1π8
  x=11π8 and 15π8

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