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The spin-only magnetic moments of $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ and $\left[\mathrm{FeF}_{6}\right]^{3-\text { in }} \mathrm{BM}$ are, respectively,
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The correct answer is:
$1.73$ and $5.92$
$$
\begin{array}{l}
\mathrm{Fe}^{3+}=3 \mathrm{~d}^{5} \\
\end{array}
$$
$\odot$ ${F}$ is $W F L$ so $\mu=5.92$ While $\mathrm{NH}_{3}$ is SFL \& pairing of electrons takes place so $\mu=1.73$
\begin{array}{l}
\mathrm{Fe}^{3+}=3 \mathrm{~d}^{5} \\
\end{array}
$$
$\odot$ ${F}$ is $W F L$ so $\mu=5.92$ While $\mathrm{NH}_{3}$ is SFL \& pairing of electrons takes place so $\mu=1.73$
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