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The standard electrode potential of $\mathrm{Zn}^{2+} / \mathrm{Zn}$ is $-0.76 \mathrm{~V}$ and that of $\mathrm{Ca}^{2+} / \mathrm{Cu}$ is $0.34 \mathrm{~V}$. The emf $(\mathrm{V})$ and the free energy change $\left(\mathrm{kJ} \mathrm{mol}^{-1}\right)$, respectively, for a Daniel cell will be
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$1.1$ and -213
$\mathrm{E}_{\mathrm{Cell}}^{0}=\mathrm{E}^{0} \mathrm{Cu}^{2+}\left|\mathrm{Cu}+\mathrm{E}^{0} \mathrm{Zn}\right| \mathrm{Zn}^{2+}$
$\mathrm{E}_{\mathrm{cell}}^{0}=0.34+0.76=+1.1 \mathrm{~V}$
$\Delta G=-2 \times 96500 \times 1.1=-213 V$
$\mathrm{E}_{\mathrm{cell}}^{0}=0.34+0.76=+1.1 \mathrm{~V}$
$\Delta G=-2 \times 96500 \times 1.1=-213 V$
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