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The standard reduction potential at $298 \mathrm{~K}$ for the following half cell reaction
$Z n^{2+}(a q)+2 e^{-} \rightarrow Z n(s) ; \quad E^{\circ}=-0.762 V$
$C r^{3+}(a q)+3 e^{-} \rightarrow C r(s) ; \quad E^{\circ}=0.740 V$
$2 H^{+}(a q)+2 e^{-} \rightarrow H_{2}(g) ; \quad E^{\circ}=0.0 V$
$F_{2}(g)+2 e^{-} \rightarrow 2 F^{-}(a q) ; \quad E^{\circ}=2.87 V$
Which of the following is strongest reducing agent ?
Options:
$Z n^{2+}(a q)+2 e^{-} \rightarrow Z n(s) ; \quad E^{\circ}=-0.762 V$
$C r^{3+}(a q)+3 e^{-} \rightarrow C r(s) ; \quad E^{\circ}=0.740 V$
$2 H^{+}(a q)+2 e^{-} \rightarrow H_{2}(g) ; \quad E^{\circ}=0.0 V$
$F_{2}(g)+2 e^{-} \rightarrow 2 F^{-}(a q) ; \quad E^{\circ}=2.87 V$
Which of the following is strongest reducing agent ?
Solution:
1619 Upvotes
Verified Answer
The correct answer is:
\( Z n(s) \)
The more negative the \( E^{\circ} \) value. The more readily the metal loses electrons. The more negative the value the stronger
is the reducing agent. Therefore, strongest reducing agent is \( \mathrm{Zn} \)
is the reducing agent. Therefore, strongest reducing agent is \( \mathrm{Zn} \)
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