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The statement pattern $[p \rightarrow(q \rightarrow p)] \rightarrow[p \rightarrow(p \vee q)]$ is
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Verified Answer
The correct answer is:
A tautology
$p \rightarrow(q \rightarrow p)$ is a tautology
$p \rightarrow(p \vee q)$ is a tautology
Hence, $[p \rightarrow(q \rightarrow p)] \rightarrow[p \rightarrow(p \vee q)]$ is a tautology
$p \rightarrow(p \vee q)$ is a tautology
Hence, $[p \rightarrow(q \rightarrow p)] \rightarrow[p \rightarrow(p \vee q)]$ is a tautology
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