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Question: Answered & Verified by Expert
The surface of certain metal is first illuminated with light of wavelength λ1=350 nm and then, by a light of wavelength λ2=540 nm. It is found that the maximum speed of the photoelectrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to
(Energy of photon =1240λin nm eV )
PhysicsDual Nature of MatterJEE Main
Options:
  • A 2.5
  • B 1.8
  • C 5.6
  • D 1.4
Solution:
2057 Upvotes Verified Answer
The correct answer is: 1.8
λ1=350 nm,  λ2=540nm,  V1V2=2V1=2V and V2=V

hcλ1=ϕ+12m2V2

hcλ2=ϕ+12mV2

hcλ1-4hcλ2=ϕ-4ϕ

hc4540-1340=3ϕ

ϕ=1.8 eV

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