Search any question & find its solution
Question:
Answered & Verified by Expert
The time in seconds required to produce a potential difference of $20 \mathrm{~V}$ across a capacitor of $1000 \mu \mathrm{F}$ when it is charged at the steady rate of $200 \mu \mathrm{C} / \mathrm{s}$ is
Options:
Solution:
2689 Upvotes
Verified Answer
The correct answer is:
$100$
Total charge
$$
\begin{aligned}
& =1000 \times 10^{-6} \times 20 \\
& =20,000 \mu \mathrm{C}
\end{aligned}
$$
$$
\text { Rate of charge }=200 \mu \mathrm{C} / \mathrm{s}
$$
$$
\therefore \text { Time taken }=\frac{20,000}{200}=100 \mathrm{sec}
$$
$$
\begin{aligned}
& =1000 \times 10^{-6} \times 20 \\
& =20,000 \mu \mathrm{C}
\end{aligned}
$$
$$
\text { Rate of charge }=200 \mu \mathrm{C} / \mathrm{s}
$$
$$
\therefore \text { Time taken }=\frac{20,000}{200}=100 \mathrm{sec}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.