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The total current supplied to the circuit by the battery is
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Verified Answer
The correct answer is:
$4 A$
$4 A$
The given circuit can be written as
$$
\mathrm{I}=\frac{6 \mathrm{~V}}{1.5 \Omega}=4 \mathrm{~A}
$$
$$
\mathrm{I}=\frac{6 \mathrm{~V}}{1.5 \Omega}=4 \mathrm{~A}
$$
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