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Question: Answered & Verified by Expert
The total number of numbers, lying between 100 and 1000 that can be formed with the digits 1,2,3,4,5, if the repetition of digits is not allowed and numbers are divisible by either 3 or 5, is
MathematicsPermutation CombinationJEE MainJEE Main 2021 (25 Feb Shift 1)
Solution:
2851 Upvotes Verified Answer
The correct answer is: 32

We need three digits numbers.

Since 1+2+3+4+5=15

So, number of possible triplets for multiple of 15 is 1×2×2

so =4×3+4×3-1×2×2=32

Alternate:

 

divisible by 5=4×3=12

Divisible by 3

123, 4, 53!=6152, 3, 43!=6241, 3, 53!=6421, 2, 33!=6                              24

Divisible by 15

1,4,5; 4,1,5; 3,4,5; 4,3,5

Required No. =24+12-4=32

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