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The translational kinetic energy of the molecules of a gas at absolute temperature ( $\mathrm{T}$ ) can be doubled
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Verified Answer
The correct answer is:
by increasing $\mathrm{T}$ to $2 \mathrm{~T}$
$$
\mathrm{E}_{\text {molecule }}=\frac{3}{2} \mathrm{kT}
$$
Kinetic energy is directly proportional to absolute temperature.
\mathrm{E}_{\text {molecule }}=\frac{3}{2} \mathrm{kT}
$$
Kinetic energy is directly proportional to absolute temperature.
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