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The truth table given below is for ( $A$ and $B$ are the inputs, $Y$ is the output).
\begin{array}{c|c|c}
\hlineA & B & Y \\
\hline 0 & 0 & 1 \\
\hline 0 & 1 & 1 \\
\hline 1 & 0 & 1 \\
\hline 1 & 1 & 0 \\
\hline
\end{array}
Options:
\begin{array}{c|c|c}
\hlineA & B & Y \\
\hline 0 & 0 & 1 \\
\hline 0 & 1 & 1 \\
\hline 1 & 0 & 1 \\
\hline 1 & 1 & 0 \\
\hline
\end{array}
Solution:
2926 Upvotes
Verified Answer
The correct answer is:
NAND
The output $\mathrm{Y}$ is a combination of AND + NOT gate. Hence, the truth table is for NAND gate
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