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The value of $\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x, a>0$, is
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Verified Answer
The correct answer is:
$\frac{\pi}{2}$
$\frac{\pi}{2}$
$$
\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x=\int_0^\pi \cos ^2 x d x=\frac{\pi}{2} .
$$
\int_{-\pi}^\pi \frac{\cos ^2 x}{1+a^x} d x=\int_0^\pi \cos ^2 x d x=\frac{\pi}{2} .
$$
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