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Question: Answered & Verified by Expert
The value of limx01-cos2xx is equal to
MathematicsLimitsJEE Main
Options:
  • A 12
  • B -12
  • C Does not exist
  • D 1
Solution:
2686 Upvotes Verified Answer
The correct answer is: Does not exist
limx01-cos2xx
=limx01-cos2xx.11+cos2x
=limx02|sinx|x.11+cos2x
Now, we have
LHL=limx0-2sinxx.11+cos2x
=-2.12=-1
RHL=limx02sinxx.11+cos2x
=2.12=1
LHLRHL
Hence, limit does not exist.

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