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Question: Answered & Verified by Expert
The value of limx0ln2-cos15xln2sin3x+1 is equal to
MathematicsLimitsJEE Main
Solution:
1808 Upvotes Verified Answer
The correct answer is: 12.5
limx0ln2-cos15xln2sin3x+1=limx0ln1+1-cos15xln21+sin3x
=limx01-cos15xsin3x2
=limx015x223x2=12252×9=12.5

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