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Question: Answered & Verified by Expert
The value of log10K for a reaction AB is
(Given: ΔrHo298K=-54.07 kJmol-1,ΔrSo298K=10J K-1mol-1
and R=8.314 JK-1mol-1;2.303×8.314×298=5705 )
ChemistryChemical EquilibriumNEET
Options:
  • A 90
  • B 100
  • C 5
  • D 10
Solution:
2068 Upvotes Verified Answer
The correct answer is: 10
ΔGo=ΔHo-TΔSo=-54.07×1000298×10=-57050 Jmol-1
ΔG°=-2.303RTlog10K
-57050=-5705log10K
log10K=10

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